If the quadratic equation ${\mathrm{px}}^{2}2\sqrt{5}\mathrm{px}+15=0$ has two equal roots, then find the value of p.
Answer :
The given quadratic equation $p{x}^{2}2\sqrt{5}px+15=0$ has two equal roots.
So, the discriminant of the quadratic equation is 0.
$\therefore {b}^{2}4ac=0\phantom{\rule{0ex}{0ex}}\Rightarrow {\left(2\sqrt{5}p\right)}^{2}4\times p\times 15=0\phantom{\rule{0ex}{0ex}}\Rightarrow 20{p}^{2}60p=0\phantom{\rule{0ex}{0ex}}\Rightarrow 20p\left(p3\right)=0\phantom{\rule{0ex}{0ex}}\Rightarrow p=0\mathrm{or}p3=0\phantom{\rule{0ex}{0ex}}\Rightarrow p=0\mathrm{or}p=3\phantom{\rule{0ex}{0ex}}$
But p cannot be zero.
Hence, the value of p is 3.
In Figure 1, a tower AB is 20 m high and BC, its shadow on the ground, is $20\sqrt{3}$ m long. Find the Sun's altitude.
Figure 1 
Answer :
Let the Sun's altitude be θ.
In ΔABC,
$\mathrm{tan}\theta =\frac{\mathrm{AB}}{\mathrm{BC}}\phantom{\rule{0ex}{0ex}}\Rightarrow \mathrm{tan}\theta =\frac{20}{20\sqrt{3}}\phantom{\rule{0ex}{0ex}}\Rightarrow \mathrm{tan}\theta =\frac{1}{\sqrt{3}}\phantom{\rule{0ex}{0ex}}\Rightarrow \mathrm{tan}\theta =\mathrm{tan}30\xb0\phantom{\rule{0ex}{0ex}}\Rightarrow \theta =30\xb0\phantom{\rule{0ex}{0ex}}$
Hence, the altitude of Sun is 30°.
Two different dice are tossed together. Find the probability that the product of the two number on the top of the dice is 6.
Answer :
When two dice are thrown simultaneously, the possible outcomes can be listed as:
1 
2 
3 
4 
5 
6 

1 
(1, 1) 
(1, 2) 
(1, 3) 
(1, 4) 
(1, 5) 
(1, 6) 
2 
(2, 1) 
(2, 2) 
(2, 3) 
(2, 4) 
(2, 5) 
(2, 6) 
3 
(3, 1) 
(3, 2) 
(3, 3) 
(3, 4) 
(3, 5) 
(3, 6) 
4 
(4, 1) 
(4, 2) 
(4, 3) 
(4, 4) 
(4, 5) 
(4, 6) 
5 
(5, 1) 
(5, 2) 
(5, 3) 
(5, 4) 
(5, 5) 
(5, 6) 
6 
(6, 1) 
(6, 2) 
(6, 3) 
(6, 4) 
(6, 5) 
(6, 6) 
∴ Total number of possible outcomes = 36
The outcomes favourable to the event 'the product of the two number on the top of the dice is 6' denoted by E are (1, 6), (2, 3), (3, 2) and (6, 1).In Figure 2, PQ is a chord of a circle with centre O and PT is a tangent. If ∠QPT = 60°, find ∠ PRQ.
Figure 2 
Answer :
In Figure 3, two tangents RQ and RP are drawn from an external point R to the circle with centre O. If ∠PRQ = 120°, then prove that OR = PR + RQ.
Figure 3 
Answer :
In figure 4, a triangle ABC is drawn to circumscribe a circle of radius 3 cm, such that the segments RD and DC are respectively of lengths 6 cm and 9 cm. If the area of âˆ†ABC is 54 cm^{2}, then find the lengths of sides AB and AC.
Figure 4 
Answer :
Solve the following quadratic equation for x :
4x^{2} + 4bx −
(a^{2} − b^{2}) = 0
Answer :
In an AP, if S_{5} + S_{7} = 167 and S_{10} = 235, then find the AP, where S_{n} denotes the sum of its first n terms.
Answer :
The points A(4, 7), B(p, 3) and C(7, 3) are the vertices of a right triangle, rightangled at B find the value of p.
Answer :
Find the relation between x and y if the points A(x, y), B(–5, 7) and C(–4, 5) are collinear.
Answer :
The 14^{th} term of an AP is twice its 8^{th} term. If its 6^{th} terms is –8, then find the sum of its first 20 terms.
Answer :
Solve for x :
$\sqrt{3}{x}^{2}2\sqrt{2}x2\sqrt{3}=0$
Answer :
The angle of elevation of an aeroplane from a point A on the ground 60°. After a flight of 15 seconds, the angle of elevation changes to 30°. If the aeroplane is flying at a constant height of 1500$\sqrt{3}$ m, find the speed of the plane in km/hr.
Answer :
If the coordinates of points A and B are (–2, –2) and (2, –4) respectively, find the coordinates of P such that $\mathrm{AP}=\frac{3}{7}\mathrm{AB}$, where P lies on the line segment AB.
Answer :
The probability of selecting a red ball at random from a jar that contains only red, blue and orange balls is $\frac{1}{4}.$ The probability of selecting a blue ball at random from the same jar is $\frac{1}{3}.$ If the jar contains 10 orange balls, find the total number of balls in the jar.
Answer :
Find the area of the minor segment of a circle of radius 14 cm, when its central angle is 60°. Also find the area of the corresponding major segment. $\left[\mathrm{Use}\mathrm{\pi}=\frac{22}{7}\right]$
Answer :
Due to sudden floods, some welfare associations jointly requested the government to get 100 tents fixed immediately and offered to contribute 50% of the cost. If the lower part of each tent is of the form of a cylinder of diameter 4.2 m and height 4 m with the conical upper part of same diameter but of height 2.8 m, and the canvas to be used costs Rs. 100 per sq. m, find the amount, the associations will have to pay. What values are shown by these associations?$\left[\mathrm{Use}\mathrm{\pi}=\frac{22}{7}\right]$
Answer :
A hemispherical bowl of internal diameter 36 cm contains liquid. This liquid is filled into 72 cylindrical bottles of diameter 6 cm. Find the height of the each bottle, if 10% liquid is wasted in this transfer.
Answer :
A cubical block of side 10 cm is surmounted by a hemisphere. What is the largest diameter that the hemisphere can have ? Find the cost of painting the total surface area of the solid so formed, at the rate of Rs 5 per 100 sq. cm. [Use π =3.14]
Answer :
504 cones, each of diameter 3.5 cm and height 3 cm, are melted and recast into a metallic sphere. Find the diameter of the sphere and hence find its surface area. [Use $\mathrm{\pi}=\frac{22}{7}$]
Answer :
The diagonal of a rectangular field is 16 metres more than the shorter side. If the longer side is 14 metres more than the shorter side, then find the lengths of the sides of the field.
Answer :
Find the 60^{th} term of the AP 8, 10, 12, ...., if it has a total of 60 terms and hence find the sum of its last 10 terms.
Answer :
A train travels at a certain average speed for a distance of 54 km and then travels a distance of 63 km at an average speed of 6 km/h more than the first speed. If it takes 3 hours to complete the total journey, what is its first speed ?
Answer :
Prove that the lengths of tangents drawn from an external point to a circle are equal.
Answer :
Prove that the tangent drawn at the midpoint of an arc of a circle is parallel to the chord joining the end points of the arc.
Answer :
Construct a Δ ABC in which AB = 6 cm, ∠ A = 30° and ∠ B = 60°. Construct another Δ AB'C' similar to Δ ABC with base AB' = 8 cm.
Answer :
At a point A, 20 metres above the level of water in a lake, the angle of elevation of a cloud is 30°. The angle of depression of the reflection of the cloud in the lake, at A is 60°. Find the distance of the cloud from A.
Answer :
A card is drawn at random from a wellshuffled deck of playing
cards.
Find the probability that the card drawn is
(i) a card of spade or an ace
(ii) a black king
(iii) neither a jack nor a king
(iv) either a king or a queen
Answer :
Find the values of k so that the area of the triangle with vertices (1, –1), (–4, 2k) and (–k, –5) is 24 sq. units.
Answer :
In Figure 5. PQRS is a square lawn with side PQ = 42 metres. Two circular flower beds are there on the sides PS and QR with centre at O, the intersection of its diagonals. Find the total area of the two flower beds (shaded parts).
Figure 5 
Answer :
From each end of a solid metal cylinder, metal was scooped out in hemispherical form of same diameter. The height of the cylinder is 10 cm and its base is of radius 4.2 cm. The rest of the cylinder is melted and converted into a cylindrical wire of 1.4 cm thickness. Find the length of the wire. $\left[\mathrm{Use}\mathrm{\pi}=\frac{22}{7}\right]$
Answer :
10th Maths Paper Solutions Set 3 : CBSE Delhi Previous Year 2013 will be available online in PDF book soon. The solutions are absolutely Free. Soon you will be able to download the solutions.