Question: 1. A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is Râ€², then the ratio R/Râ€² is
(a) 1/25 (b) 1/5 (c) 5 (d) 25
Answer:- (d) 25
The piece of wire having resistance equal to R is cut into five equal parts.
Question: 2:- Which of the following terms does not represent electrical power in a circuit?
(a) I2R (b) IR2 (c) VI (d) V2/R
Answer:- (b) IR2
We know that Power (P) = VI
After substituting the value of V = IR in this we get
P = (IR) I = I x R x I = I2R, Thus P = I2R
Thus, P cannot be expressed as IR2
Question: 3:- An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the power consumed will be
(a) 100 W (b) 75 W (c) 50 W (d) 25 W
Answer:- (d) 25 W
Potential difference, V = 220V, Power, P = 100W
Therefore, power consumption at 100V =?
To solve this problem, first of all resistance of the bulb is to be calculated.
Thus, bulb will consume power of 25W at 110V
Question: 4:- Two conducting wires of the same material and of equal lengths and equal diameters are first connected in series and then parallel in a circuit across the same potential difference. The ratio of heat produced in series and parallel combinations would be
(a) 1:2 (b) 2:1 (c) 1:4 (d) 4:1
Answer: (c) 1 : 4
Let the potential difference = V,
Resistance of the wire = R
Resistance when the given wires connected in series = Rs
Resistance when the given wires connected in parallel = Rp
Heat produced when the given wires connected in series = Hs
Heat produced when the given wires connected in parallel = Hp
Thus, resistance Rs when the given two wires connected in series = R + R = 2R
Question: 5. How is a voltmeter connected in the circuit to measure the potential difference between two points?
Answer: Voltmeter is connected into parallel to measure the potential difference between two points in a circuit.
Question: 6. A copper wire has diameter 0.5 mm and resistivity of 1.6 Ã— 10 8 Î© m. What will be the length of this wire to make its resistance 10 Î©? How much does the resistance change if the diameter is doubled?
Given, Diameter of wire = 0.5 mm
Question: 7. The values of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below
Plot a graph between V and I and calculate the resistance of that resistor.
Since slope of the graph will give the value of resistance, thus
Let consider two points A and B on the slope.
Draw two lines from B along X-axis and from A along Y-axis, which meets at point C
Now, BC = 10.2 V 3.4 V = 6.8 V
AC = 3 1 = 2 ampere
Question: 8. When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.
Given, Potential difference, V = 12V
Current ( I ) across the resistor = 2.5mA = 2.5 x 10 -3 = 0.0025 A
Resistance, R =?
Question: 9. A battery of 9 V is connected in series with resistors of 0.2 Î©, 0.3 Î©, 0.4 Î© , 0.5 Î© and 12 Î©, respectively. How much current would flow through the 12 Î© resistor?
Given, potential difference, V = 9V
Resistance of resistors which are connected in series = 0.2 Î©, 0.3 Î©, 0.4 Î© , 0.5 Î© and 12 Î© respectively
Current through resistor having resistance equal to 12Î© =?
Total effective resistance, R = 0.2 Î© + 0.3 Î© + 0.4 Î© + 0.5 Î© + 12 Î© = 13.4 Î©
Since, there is no division of electric current, in the circuit if resistors are connected in series, thus, resistance through the resistor having resistance equal to 12 Î© = 0.671 A
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