NCERT Solutions of Human Eye and Colourful World Class 10
<< Refraction of Light Through a Prism: NCERT Solution - Part - 2 >>

Human Eye and the Colourful World

NCERT Solution - Part - 1

Question 1 :- The human eye can focus objects at different distances by adjusting the focal length of the eye lens. This is due to

  1. Presbyopia
  2. Accommodation
  3. Near sightedness
  4. Far sightedness

Answer: (b) Accommodation

Question 2 - The human eye forms the image of an object at its

  1. Cornea
  2. Iris
  3. Pupil
  4. Retina

Answer:- (d) Retina

Question 3 :- The least distance of distinct vision for a young adult with normal vision is about

  1. 25 m.
  2. 2.5 cm.
  3. 25 cm.
  4. 2.5 m.

Answer: (c) 25 cm

Question 4 :- The change in focal length of an eye lens is caused by the action of the

  1. Pupil
  2. Retina
  3. Ciliary muscles
  4. Iris

Answer: (c) Ciliary muscles

Question 5 - A person needs a lens of power 5.5 dioptres for correcting his distant vision. For correcting his near vision he needs a lens of power +1.5 dioptre. What is the focal length of the lens required for correcting (i) distant vision, and (ii) near vision?

Answer: The power of a lens can be calculated by following formula:

Human Eye 1

Hence, the focal length of the required lens for near vision = +0.67 cm

Question 6 - The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?

Answer: In the given situation, the person shall be able to see a distant object clearly if the image of that object would be formed at his far point, which is 80 cm.

Given; object distance u = ‚

Image distance v = -80 cm = - 0.8 m

The focal length and power of the required lens can be calculated by using the following formula:

Human Eye 2

The negative sign shows that the lens is a concave lens.

The power of lens = -1.25 D



NCERT Solutions of Human Eye and Colourful World Class 10
<< Refraction of Light Through a Prism: NCERT Solution - Part - 2 >>

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