Construct the following quadrilaterals.
(i) Quadrilateral ABCD
AB = 4.5 cm
BC = 5.5 cm
CD = 4 cm
AD = 6 cm
AC = 7 cm
(ii) Quadrilateral JUMP
JU = 3.5 cm
UM = 4 cm
MP = 5 cm
PJ = 4.5 cm
PU = 6.5 cm
(iii) Parallelogram MORE
OR = 6 cm
RE = 4.5 cm
EO = 7.5 cm
(iv) Rhombus BEST
BE = 4.5 cm
ET = 6 cm
Answer :
(i) Firstly, a rough sketch of this quadrilateral can be drawn as follows.
(1) ΔABC can be constructed by using the given measurements as follows.
(2) Vertex D is 6 cm away from vertex A. Therefore, while taking A as centre, draw an arc of radius 6 cm.
(3) Taking C as centre, draw an arc of radius 4 cm, cutting the previous arc at point D. Join D to A and C.
ABCD is the required quadrilateral.
(ii)Firstly, a rough sketch of this quadrilateral can be drawn as follows.
(1) Δ JUP can be constructed by using the given measurements as follows.
(2) Vertex M is 5 cm away from vertex P and 4 cm away from vertex U. Taking P and U as centres, draw arcs of radii 5 cm and 4 cm respectively. Let the point of intersection be M.
(3) Join M to P and U.
JUMP is the required quadrilateral.
(iii)We know that opposite sides of a parallelogram are equal in length and also these are parallel to each other.
Hence, ME = OR, MO = ER
A rough sketch of this parallelogram can be drawn as follows.
(1) Δ EOR can be constructed by using the given measurements as follows.
(2) Vertex M is 4.5 cm away from vertex O and 6 cm away from vertex E. Therefore, while taking O and E as centres, draw arcs of 4.5 cm radius and 6 cm radius respectively. These will intersect each other at point M.
(3) Join M to O and E.

MORE is the required parallelogram. 
(iv)We know that all sides of a rhombus are of the same measure.
Hence, BE = ES = ST = TB
A rough sketch of this rhombus can be drawn as follows.
(1) Δ BET can be constructed by using the given measurements as follows.
(2) Vertex S is 4.5 cm away from vertex E and also from vertex T. Therefore, while taking E and T as centres, draw arcs of 4.5 cm radius, which will be intersecting each other at point S.
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Construct the following quadrilaterals.
(i) Quadrilateral LIFT
LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm
(ii) Quadrilateral GOLD
OL = 7.5 cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10 cm
(iii) Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm
Answer :
(i) A rough sketch of this quadrilateral can be drawn as follows.
(1) Δ ITL can be constructed by using the given measurements as follows.
(2) Vertex F is 4.5 cm away from vertex L and 3 cm away from vertex I. Therefore, while taking L and I as centres, draw arcs of 4.5 cm radius and 3 cm radius respectively, which will be intersecting each other at point F.
(3) Join F to T and F to I.

LIFT is the required quadrilateral. 
(ii)A rough sketch of this quadrilateral can be drawn as follows.
(1) Δ GDL can be constructed by using the given measurements as follows.
(2) Vertex O is 10 cm away from vertex D and 7.5 cm away from vertex L. Therefore, while taking D and L as centres, draw arcs of 10 cm radius and 7.5 cm radius respectively. These will intersect each other at point O.
(3) Join O to G and L.

GOLD is the required quadrilateral. 
(iii) We know that the diagonals of a rhombus always bisect each other at 90º. Let us assume that these are intersecting each other at point O in this rhombus.
Hence, EO = OD = 3.25 cm
A rough sketch of this rhombus can be drawn as follows.
(1) Draw a line segment BN of 5.6 cm and also draw its perpendicular bisector. Let it intersect the line segment BN at point O.
(2) Taking O as centre, draw arcs of 3.25 cm radius to intersect the perpendicular bisector at point D and E.
(3) Join points D and E to points B and N.

BEND is the required quadrilateral. 
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Construct the following quadrilaterals.
(i) Quadrilateral MORE
MO = 6 cm
OR = 4.5 cm
∠ M = 60°
∠ O = 105°
∠ R = 105°
(ii) Quadrilateral PLAN
PL = 4 cm
LA = 6.5 cm
∠ P = 90°
∠ A = 110°
∠ N = 85°
(iii) Parallelogram HEAR
HE = 5 cm
EA = 6 cm
∠ R = 85°
(iv) Rectangle OKAY
OK = 7 cm
KA = 5 cm
Answer :
Construct the following quadrilaterals,
(i) Quadrilateral DEAR
DE = 4 cm
EA = 5 cm
AR = 4.5 cm
∠ E = 60°
∠ A = 90°
(ii) Quadrilateral TRUE
TR = 3.5 cm
RU = 3 cm
UE = 4 cm
∠ R = 75°
∠ U = 120°
Answer :
Draw the following:
The square READ with RE = 5.1 cm
Answer :
Draw the following:
A rhombus whose diagonals are 5.2 cm and 6.4 cm long.
Answer :
Draw the following:
A rectangle with adjacent sides of length 5 cm and 4 cm.
Answer :
Draw the following:
A parallelogram OKAY where OK = 5.5 cm and KA = 4.2 cm.
Answer :
Maths  NCERT Solution  Maths : CBSE NCERT Exercise Solutions for Class 8th for Practical Geometry ( Exercise 4.1, 4.2, 4.3, 4.4, 4.5 ) will be available online in PDF book form soon. The solutions are absolutely Free. Soon you will be able to download the solutions.
Exercise 4.1 
Question 1 
Exercise 4.2 
Question 1 
Exercise 4.3 
Question 1 
Exercise 4.4 
Question 1 
Exercise 4.5 
Question 1 
Question 2 
Question 3 
Question 4 