NCERT Solutions for Class 8 Maths Maths - NCERT Solution Chapter 4

Practical Geometry Class 8

Chapter 4 Practical Geometry Exercise 4.1, 4.2, 4.3, 4.4, 4.5 Solutions

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Exercise 4.1 : Solutions of Questions on Page Number : 60

Q1 :  

Construct the following quadrilaterals.

(i) Quadrilateral ABCD

AB = 4.5 cm

BC = 5.5 cm

CD = 4 cm

AD = 6 cm

AC = 7 cm

(ii) Quadrilateral JUMP

JU = 3.5 cm

UM = 4 cm

MP = 5 cm

PJ = 4.5 cm

PU = 6.5 cm

(iii) Parallelogram MORE

OR = 6 cm

RE = 4.5 cm

EO = 7.5 cm

(iv) Rhombus BEST

BE = 4.5 cm

ET = 6 cm


Answer :

(i) Firstly, a rough sketch of this quadrilateral can be drawn as follows.

(1) ΔABC can be constructed by using the given measurements as follows.

(2) Vertex D is 6 cm away from vertex A. Therefore, while taking A as centre, draw an arc of radius 6 cm.

(3) Taking C as centre, draw an arc of radius 4 cm, cutting the previous arc at point D. Join D to A and C.

ABCD is the required quadrilateral.

(ii)Firstly, a rough sketch of this quadrilateral can be drawn as follows.

(1) Δ JUP can be constructed by using the given measurements as follows.

(2) Vertex M is 5 cm away from vertex P and 4 cm away from vertex U. Taking P and U as centres, draw arcs of radii 5 cm and 4 cm respectively. Let the point of intersection be M.

(3) Join M to P and U.

JUMP is the required quadrilateral.

(iii)We know that opposite sides of a parallelogram are equal in length and also these are parallel to each other.

Hence, ME = OR, MO = ER

A rough sketch of this parallelogram can be drawn as follows.

(1) Δ EOR can be constructed by using the given measurements as follows.

(2) Vertex M is 4.5 cm away from vertex O and 6 cm away from vertex E. Therefore, while taking O and E as centres, draw arcs of 4.5 cm radius and 6 cm radius respectively. These will intersect each other at point M.

(3) Join M to O and E.

MORE is the required parallelogram.

(iv)We know that all sides of a rhombus are of the same measure.

Hence, BE = ES = ST = TB

A rough sketch of this rhombus can be drawn as follows.

(1) Δ BET can be constructed by using the given measurements as follows.

(2) Vertex S is 4.5 cm away from vertex E and also from vertex T. Therefore, while taking E and T as centres, draw arcs of 4.5 cm radius, which will be intersecting each other at point S.

Answer needs Correction? Click Here

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Exercise 4.2 : Solutions of Questions on Page Number : 62

Q1 :  

Construct the following quadrilaterals.

(i) Quadrilateral LIFT

LI = 4 cm

IF = 3 cm

TL = 2.5 cm

LF = 4.5 cm

IT = 4 cm

(ii) Quadrilateral GOLD

OL = 7.5 cm

GL = 6 cm

GD = 6 cm

LD = 5 cm

OD = 10 cm

(iii) Rhombus BEND

BN = 5.6 cm

DE = 6.5 cm


Answer :

(i) A rough sketch of this quadrilateral can be drawn as follows.

(1) Δ ITL can be constructed by using the given measurements as follows.

(2) Vertex F is 4.5 cm away from vertex L and 3 cm away from vertex I. Therefore, while taking L and I as centres, draw arcs of 4.5 cm radius and 3 cm radius respectively, which will be intersecting each other at point F.

(3) Join F to T and F to I.

LIFT is the required quadrilateral.

(ii)A rough sketch of this quadrilateral can be drawn as follows.

(1) Δ GDL can be constructed by using the given measurements as follows.

(2) Vertex O is 10 cm away from vertex D and 7.5 cm away from vertex L. Therefore, while taking D and L as centres, draw arcs of 10 cm radius and 7.5 cm radius respectively. These will intersect each other at point O.

(3) Join O to G and L.

GOLD is the required quadrilateral.

(iii) We know that the diagonals of a rhombus always bisect each other at 90º. Let us assume that these are intersecting each other at point O in this rhombus.

Hence, EO = OD = 3.25 cm

A rough sketch of this rhombus can be drawn as follows.

(1) Draw a line segment BN of 5.6 cm and also draw its perpendicular bisector. Let it intersect the line segment BN at point O.

(2) Taking O as centre, draw arcs of 3.25 cm radius to intersect the perpendicular bisector at point D and E.

(3) Join points D and E to points B and N.

BEND is the required quadrilateral.

Answer needs Correction? Click Here

<< Previous Chapter 3 : Understanding Quadrilaterals Next Chapter 5 : Data Handling >>

Exercise 4.3 : Solutions of Questions on Page Number : 64

Q1 :  

Construct the following quadrilaterals.

(i) Quadrilateral MORE

MO = 6 cm

OR = 4.5 cm

∠ M = 60°

∠ O = 105°

∠ R = 105°

(ii) Quadrilateral PLAN

PL = 4 cm

LA = 6.5 cm

∠ P = 90°

∠ A = 110°

∠ N = 85°

(iii) Parallelogram HEAR

HE = 5 cm

EA = 6 cm

∠ R = 85°

(iv) Rectangle OKAY

OK = 7 cm

KA = 5 cm


Answer :

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Exercise 4.4 : Solutions of Questions on Page Number : 67

Q1 :  

Construct the following quadrilaterals,

(i) Quadrilateral DEAR

DE = 4 cm

EA = 5 cm

AR = 4.5 cm

∠ E = 60°

∠ A = 90°

(ii) Quadrilateral TRUE

TR = 3.5 cm

RU = 3 cm

UE = 4 cm

∠ R = 75°

∠ U = 120°


Answer :

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Exercise 4.5 : Solutions of Questions on Page Number : 68

Q1 :  

Draw the following:

The square READ with RE = 5.1 cm


Answer :

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Q2 :  

Draw the following:

A rhombus whose diagonals are 5.2 cm and 6.4 cm long.


Answer :

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Q3 :  

Draw the following:

A rectangle with adjacent sides of length 5 cm and 4 cm.


Answer :

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Q4 :  

Draw the following:

A parallelogram OKAY where OK = 5.5 cm and KA = 4.2 cm.


Answer :

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Maths - NCERT Solution - Maths : CBSE NCERT Exercise Solutions for Class 8th for Practical Geometry ( Exercise 4.1, 4.2, 4.3, 4.4, 4.5 ) will be available online in PDF book form soon. The solutions are absolutely Free. Soon you will be able to download the solutions.

Exercise 4.1
Question 1
Exercise 4.2
Question 1
Exercise 4.3
Question 1
Exercise 4.4
Question 1
Exercise 4.5
Question 1
Question 2
Question 3
Question 4