In a reaction, 5.3 g of sodium carbonate reacted with 6 g of
ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g
water and 8.2 g of sodium ethanoate. Show that these observations
are in agreement with the law of conservation of mass.
Sodium carbonate + ethanoic acid
ethanoate + carbon dioxide + water
In the given reaction, sodium carbonate reacts with
ethanoic acid to produce sodium ethanoate, carbon
dioxide, and water.
Mass of sodium carbonate = 5.3 g
Mass of ethanoic acid = 6 g (Given)
Mass of sodium ethanoate = 8.2 g (Given)
Mass of carbon dioxide = 2.2 g (Given)
Mass of water = 0.9 g (Given)
Now, total mass before the reaction = (5.3 +
= 11.3 g
And, total mass after the reaction = (8.2 +
2.2 + 0.9) g
= 11.3 g
mass before the reaction = Total mass after the reaction
Hence, the given observations are in agreement
with the law of conservation of mass.
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