A farmer moves along the boundary of a square field of side
10 m in 40s. What will be the magnitude of
displacement of the farmer at the end of 2 minutes 20
The farmer takes 40 s to cover 4
10 = 40 m.
In 2 min and 20 s (140 s), he will cover a
Therefore, the farmer completes rounds (3 complete
rounds and a half round) of the field in 2 min and 20 s.
That means, after 2 min 20 s, the farmer will be at the
opposite end of the starting point.
Now, there can be two extreme cases.
Case I: Starting point is a corner
point of the field.
In this case, the farmer will be at the
diagonally opposite corner of the field after 2 min 20
Therefore, the displacement will be equal to the diagonal of the
Hence, the displacement will be
Case II: Starting point is the middle
point of any side of the field.
In this case the farmer will be at the middle point of the
opposite side of the field after 2 min 20 s.
Therefore, the displacement will be equal to the side of the
field, i.e., 10 m.
For any other starting point, the displacement will be between
14.1 m and 10 m.
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